Optimal. Leaf size=113 \[ -\frac {\text {Int}\left (\frac {1}{x^2 \tan ^{-1}(a x)},x\right )}{a c^3}+\frac {a x}{c^3 \left (a^2 x^2+1\right ) \tan ^{-1}(a x)}+\frac {a x}{c^3 \left (a^2 x^2+1\right )^2 \tan ^{-1}(a x)}-\frac {3 \text {Ci}\left (2 \tan ^{-1}(a x)\right )}{2 c^3}-\frac {\text {Ci}\left (4 \tan ^{-1}(a x)\right )}{2 c^3}-\frac {1}{a c^3 x \tan ^{-1}(a x)} \]
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Rubi [A] time = 0.66, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {1}{x \left (c+a^2 c x^2\right )^3 \tan ^{-1}(a x)^2} \, dx \]
Verification is Not applicable to the result.
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Rubi steps
\begin {align*} \int \frac {1}{x \left (c+a^2 c x^2\right )^3 \tan ^{-1}(a x)^2} \, dx &=-\left (a^2 \int \frac {x}{\left (c+a^2 c x^2\right )^3 \tan ^{-1}(a x)^2} \, dx\right )+\frac {\int \frac {1}{x \left (c+a^2 c x^2\right )^2 \tan ^{-1}(a x)^2} \, dx}{c}\\ &=\frac {a x}{c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}-a \int \frac {1}{\left (c+a^2 c x^2\right )^3 \tan ^{-1}(a x)} \, dx+\left (3 a^3\right ) \int \frac {x^2}{\left (c+a^2 c x^2\right )^3 \tan ^{-1}(a x)} \, dx+\frac {\int \frac {1}{x \left (c+a^2 c x^2\right ) \tan ^{-1}(a x)^2} \, dx}{c^2}-\frac {a^2 \int \frac {x}{\left (c+a^2 c x^2\right )^2 \tan ^{-1}(a x)^2} \, dx}{c}\\ &=-\frac {1}{a c^3 x \tan ^{-1}(a x)}+\frac {a x}{c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}+\frac {a x}{c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac {\operatorname {Subst}\left (\int \frac {\cos ^4(x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{c^3}+\frac {3 \operatorname {Subst}\left (\int \frac {\cos ^2(x) \sin ^2(x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{c^3}-\frac {\int \frac {1}{x^2 \tan ^{-1}(a x)} \, dx}{a c^3}-\frac {a \int \frac {1}{\left (c+a^2 c x^2\right )^2 \tan ^{-1}(a x)} \, dx}{c}+\frac {a^3 \int \frac {x^2}{\left (c+a^2 c x^2\right )^2 \tan ^{-1}(a x)} \, dx}{c}\\ &=-\frac {1}{a c^3 x \tan ^{-1}(a x)}+\frac {a x}{c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}+\frac {a x}{c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac {\operatorname {Subst}\left (\int \frac {\cos ^2(x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{c^3}-\frac {\operatorname {Subst}\left (\int \left (\frac {3}{8 x}+\frac {\cos (2 x)}{2 x}+\frac {\cos (4 x)}{8 x}\right ) \, dx,x,\tan ^{-1}(a x)\right )}{c^3}+\frac {\operatorname {Subst}\left (\int \frac {\sin ^2(x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{c^3}+\frac {3 \operatorname {Subst}\left (\int \left (\frac {1}{8 x}-\frac {\cos (4 x)}{8 x}\right ) \, dx,x,\tan ^{-1}(a x)\right )}{c^3}-\frac {\int \frac {1}{x^2 \tan ^{-1}(a x)} \, dx}{a c^3}\\ &=-\frac {1}{a c^3 x \tan ^{-1}(a x)}+\frac {a x}{c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}+\frac {a x}{c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac {\operatorname {Subst}\left (\int \frac {\cos (4 x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{8 c^3}-\frac {3 \operatorname {Subst}\left (\int \frac {\cos (4 x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{8 c^3}-\frac {\operatorname {Subst}\left (\int \frac {\cos (2 x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{2 c^3}+\frac {\operatorname {Subst}\left (\int \left (\frac {1}{2 x}-\frac {\cos (2 x)}{2 x}\right ) \, dx,x,\tan ^{-1}(a x)\right )}{c^3}-\frac {\operatorname {Subst}\left (\int \left (\frac {1}{2 x}+\frac {\cos (2 x)}{2 x}\right ) \, dx,x,\tan ^{-1}(a x)\right )}{c^3}-\frac {\int \frac {1}{x^2 \tan ^{-1}(a x)} \, dx}{a c^3}\\ &=-\frac {1}{a c^3 x \tan ^{-1}(a x)}+\frac {a x}{c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}+\frac {a x}{c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac {\text {Ci}\left (2 \tan ^{-1}(a x)\right )}{2 c^3}-\frac {\text {Ci}\left (4 \tan ^{-1}(a x)\right )}{2 c^3}-2 \frac {\operatorname {Subst}\left (\int \frac {\cos (2 x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{2 c^3}-\frac {\int \frac {1}{x^2 \tan ^{-1}(a x)} \, dx}{a c^3}\\ &=-\frac {1}{a c^3 x \tan ^{-1}(a x)}+\frac {a x}{c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}+\frac {a x}{c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac {3 \text {Ci}\left (2 \tan ^{-1}(a x)\right )}{2 c^3}-\frac {\text {Ci}\left (4 \tan ^{-1}(a x)\right )}{2 c^3}-\frac {\int \frac {1}{x^2 \tan ^{-1}(a x)} \, dx}{a c^3}\\ \end {align*}
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Mathematica [A] time = 1.78, size = 0, normalized size = 0.00 \[ \int \frac {1}{x \left (c+a^2 c x^2\right )^3 \tan ^{-1}(a x)^2} \, dx \]
Verification is Not applicable to the result.
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fricas [A] time = 0.44, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {1}{{\left (a^{6} c^{3} x^{7} + 3 \, a^{4} c^{3} x^{5} + 3 \, a^{2} c^{3} x^{3} + c^{3} x\right )} \arctan \left (a x\right )^{2}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 1.65, size = 0, normalized size = 0.00 \[ \int \frac {1}{x \left (a^{2} c \,x^{2}+c \right )^{3} \arctan \left (a x \right )^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {{\left (a^{5} c^{3} x^{5} + 2 \, a^{3} c^{3} x^{3} + a c^{3} x\right )} \mathit {sage}_{0} x \arctan \left (a x\right ) + 1}{{\left (a^{5} c^{3} x^{5} + 2 \, a^{3} c^{3} x^{3} + a c^{3} x\right )} \arctan \left (a x\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [A] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {1}{x\,{\mathrm {atan}\left (a\,x\right )}^2\,{\left (c\,a^2\,x^2+c\right )}^3} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {\int \frac {1}{a^{6} x^{7} \operatorname {atan}^{2}{\left (a x \right )} + 3 a^{4} x^{5} \operatorname {atan}^{2}{\left (a x \right )} + 3 a^{2} x^{3} \operatorname {atan}^{2}{\left (a x \right )} + x \operatorname {atan}^{2}{\left (a x \right )}}\, dx}{c^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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